TLS Online TPP Program

#Question id: 27360


The same culture (with the m and K, values as computed above) is cultivated in a 10 L chemostat being operated with a 50 mL min-1 sterile feed containing 50 g L-1 of substrate. Assuming an overall yield coefficient of 0.3 (g- DCW) (g- substrate), the respective values of the outlet biomass and substrate concentrations are

#Section 5: Bioprocess Engineering and Process Biotechnology
  1. 15 g/L, 0.048 g/L
  2. 15 g/L, 0.48 g/L
  3. 48 g/L, 15 g/L

  4. 4.8 g/L, 4.8 g/L

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TLS Online TPP Program

#Question id: 14249

#Section 5: Bioprocess Engineering and Process Biotechnology

Aspartase enzyme is used industrially for manufacture of aspartic acid, a component of low-calorie sweetener. Fumaric acid and ammonia are converted to aspartic acid according to the equation:

 
                                        
Under investigation is a process using aspartase in intact Bacillus cadaveris cells. In the substrate range of interest, the conversion can be described using Michaelis-Menten kinetics with K m 4.0 gl-1. The substrate solution contains 15% (w/v) ammonium fumarate; enzyme is added in the form of lyophilised cells and the reaction stopped when 85% of the substrate is converted. At 32⁰C vmax for the enzyme is 5.9 g l-1h-1 and its half-life is 10.5 d. At 37⁰C Vmax increases to 8.5 g l- 1 h- I but the half-life is reduced to 2.3 d. The average downtime between batch reactions is 28 h. calculate the reactor volume required to produce 5000 tonnes of aspartic acid per year

TLS Online TPP Program

#Question id: 14250

#Section 5: Bioprocess Engineering and Process Biotechnology

A stirred-tank reactor is to be scaled down from 10 m3 to 0.1 m3. The dimensions of the large tank are: Dt = 2 m; Di = 0.5 m; N = 100 rpm. What would be the required rotational speed of the impeller in the small tank if impeller Re number is constant?
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TLS Online TPP Program

#Question id: 14251

#Section 5: Bioprocess Engineering and Process Biotechnology

Yeast cells are recovered from a fermentation broth by using a tubular centrifuge. Sixty percent (60%) of the cells are recovered at a flow rate of 12 l/min with a rotational speed of 4000 rpm. Recovery is inversely proportional to flow rate. a. To increase the recovery of cells to 95% at the same flow rate, what should be the rpm of the centrifuge?
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TLS Online TPP Program

#Question id: 14252

#Section 5: Bioprocess Engineering and Process Biotechnology

Yeast cells are recovered from a fermentation broth by using a tubular centrifuge. Sixty percent (60%) of the cells are recovered at a flow rate of 12 l/min with a rotational speed of 4000 rpm. Recovery is inversely proportional to flow rate. At a constant rpm of 4000 rpm, what should be the flow rate to result in 95% cell recovery?
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TLS Online TPP Program

#Question id: 14253

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  Determine the volume of the packed bed for 95% glucose conversion. Bed diameter is D0 = 0.2 m. Neglect the growth of the hybridomas and assume first order kinetics. 

TLS Online TPP Program

#Question id: 14254

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  Determine the height of the packed bed for 95% glucose conversion. Bed diameter is D0 = 0.2 m. Neglect the growth of the hybridomas and assume first order kinetics.