TLS Online TPP Program

#Question id: 2981


For the nuclear envelope to be broken down as cells go from prophase to prometaphase during mitosis, the nuclear lamina has to be disassembled. Which of the following statement is incorrect?

#Unit 2. Cellular Organization
  1.  Phosphorylation of lamins A, B and C results in disassembly of the intermediate filament lattice into lamin dimers.

  2. Due to their C-terminal myristoylation, lamin B dimers remain associated with the nuclear membrane.

  3.  Depolymerization of the nuclear lamin filaments leads to the disintegration of the nuclear lamina meshwork and contributes to disassembly of the nuclear envelope.

  4. In telophase, removal of the phosphates by specific phosphatases promotes lamin reassembly, which is critical to re-formation of a nuclear envelope around the daughter chromosomes.

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TLS Online TPP Program

#Question id: 4663

#Unit 3. Fundamental Processes

Which two polymerases function in transcriptional repression directed by nuclear siRNAs in plants?

TLS Online TPP Program

#Question id: 4662

#Unit 3. Fundamental Processes

Transcriptional activation by Pol II initiates transcription, polymerase pauses after transcribing fewer than 100 nucleotides due to the action of the elongation inhibitor such as

TLS Online TPP Program

#Question id: 4661

#Unit 3. Fundamental Processes

In bacteria two components regulatory systems contain a domain can have function such as controlling the direction in which the bacterium swims in response to a concentration gradient of nutrients is known as

TLS Online TPP Program

#Question id: 4660

#Unit 3. Fundamental Processes

Two-component system regulating response to low Gln,

a) Glutamine dissociates from the sensor domain in the NtrB protein, leading to activation of a histidine kinase transmitter domain in NtrB

b) glutamine binds to a sensor domain of NtrB, causing a conformational change in the protein that inhibits its histidine kinase activity, the regulatory domain of NtrC blocks its DNA-binding domain from binding the glnA enhancers.

c) Activated transmitter domain of NtrB that transfers the γ-phosphate of ATP to a histidine residue (H), this phosphohistidine then transfers the phosphate to an aspartic acid residue (D) in the NtrC protein

d) This causes a conformational change in NtrC that unmasks the NtrC DNA-binding domain so that it can bind to the glnA enhancers

Which of the following combination is correct?

TLS Online TPP Program

#Question id: 4659

#Unit 3. Fundamental Processes

Many bacterial responses are controlled by two component regulatory systems. What will happen at the high concentration of glutamine and at the low concentration of glutamine?

a) At high concentrations glutamine binds to a sensor domain of NtrB conformational change in the protein that inhibits its histidine kinase activity

b) NtrC phosphorylation takes place causes a conformational change in NtrC that unmasks the NtrC DNA-binding domain so that it can bind to the glnA enhancers

c) At the same time, the regulatory domain of NtrC blocks its DNA-binding domain from binding the glnA enhancers

d) At low concentrations of glutamine dissociates from the sensor domain in the NtrB protein, leading to activation of a histidine kinase transmitter domain

Which of the following given combination is correct?

TLS Online TPP Program

#Question id: 4561

#Unit 3. Fundamental Processes

Which factor recruits capping enzyme?