#Question id: 5735
#Unit 8. Inheritance Biology
Aneuploids may arise through nondisjunction, the failure of homologous chromosomes or sister chromatids to separate in meiosis. Following some statement are correct.
A) Meiosis I non-disjunction leads to produce all gamete become aneuploidy
B) Meiosis II non-disjunction leads to produce half of gametes n+1 other half normal haploid
C) Meiosis I non-disjunction leads to produce half of gametes n+1 other half n-1
D) Either meiosis I or meiosis II non-disjunction leads to produce all aneuploidy gamete
#Question id: 5736
#Unit 8. Inheritance Biology
Two zygote in which one A is 44+XYY and another B is 44+XXX karyotype is best described by
#Question id: 5726
#Unit 8. Inheritance Biology
Following diagram represents the sequence of genes in a normal chromosome of a plant species
CORRECT combination for chromosomal mutation using
#Question id: 5723
#Unit 8. Inheritance Biology
An individual heterozygous for a reciprocal translocation possesses the following chromosomes
I- nonviability II – Viability
III- only translocated chromosome IV- only normal chromosome
V- one translocated another normal
Which of the following above chromosome constituent and feature in their gamete result from?
A- alternate B- adjacent-1 C- adjacent-2
#Question id: 23966
#Unit 8. Inheritance Biology
#Question id: 5734
#Unit 8. Inheritance Biology
Following is heterozygote for inversion?
Following some statement given for above abnormality?
A) There is a less probability of a crossover occurring within inversion region and producing an enviable cross over meiotic product.
B) Chromosomes that have engaged in crossing-over separate in the normal fashion, without the creation of a bridge
C) The crossover produces chromatids that contain duplication and a deletion for different parts of the chromosome results non viable gamete
D) Double cross over within inversion loop will be results all viable gamete of parental and recombinant