Practice Questions

  1. Home
  2. Free Resources
  3. Practice Questions
  4. 56788
TLS Online TPP Program

#Question id: 12349

Males in a population differ in the time they spend displaying to females. A researcher hypothesizes that predators are responsible for these differences. Males display for longer durations when there are no predators in the vicinity and for shorter durations when there is a predator nearby. Which of the following study designs is the most appropriate test of this hypothesis?

#Unit 10. Ecological Principles
  1. Map predator distribution in the area; measure the abundance of females; quantify the natural variation in male display rates in areas without predators
  2. Measure display  rates of  males at  the beginning  of  the breeding season; remove all  predators from the study site; then measure male display rates later in the breeding season; repeat for multiple populations
  3. Measure display rates of males in areas with and without predators; randomly assign males to two treatments: (i) capture and release back in original area (ii) capture and switch between areas; measure display rates for all experimental males
  4. Measure display rates of males in areas with and without predators; randomly assign males to two treatments: (i) addition of females to the area (ii) removal of females from the area; measure display rates for all experimental males
More Questions
TLS Online TPP Program

#Question id: 10422

#Unit 6. System Physiology – Plant

Arabidopsis contains five genes encoding phytochromes, PHYA–PHYE, four of the five phytochromes appear mostly light-stable in the plant and function primarily in the regulation of LFRs and of shade avoidance involving changes in the R:FR ratio.
TLS Online TPP Program

#Question id: 10458

#Unit 6. System Physiology – Plant

Which of the following statements is not true for cry proteins?
TLS Online TPP Program

#Question id: 10500

#Unit 6. System Physiology – Plant

Orange carotenoid protein (OCP) is involve in the photoprotection, these protein complex function as light intensity sensor provides;
TLS Online TPP Program

#Question id: 10499

#Unit 6. System Physiology – Plant

Stomata from intact, attached leaves of Arabidopsis illuminated with blue, red, and green light in a growth chamber, increases and decreases their aperture in response to light.

 

Find the CORRECT statements from the above graph.

i) Stomatal aperture increases when the green light is turned off, and close when the green light is turned on again

ii) Stomata from the phototropin-less double mutant phot1/phot2 respond to blue light and open further when green light is turned off

iii) stomata from the zeaxanthin less mutant npq1 do not respond to blue light and least effect to opening of the stomata further when green light is turned off

iv) the npq1 mutant and phot1/phot2 double mutant response indicate that the green reversal of the blue-light response requires zeaxanthin but also phototropin
TLS Online TPP Program

#Question id: 10498

#Unit 6. System Physiology – Plant

Which one of the following inhibitor that inhibits blue light–stimulated stomatal opening and the inhibition is concentration dependent, while does not block red light–stimulated opening.
TLS Online TPP Program

#Question id: 10497

#Unit 6. System Physiology – Plant

Blue light stimulated opening of stomata, closing of stomata is also takes place by many other such mutants and mechanisms such as,

a.) npq1 mutants leads to closing of stomata

b.) In high PPFD leads to conversion of violaxanthin to zeaxanthin which will  leads to closing of stomata

c.) Green light in the 500 to 600 nm region of the spectrum, abolishes the opening of stomata

d.) Mutant of phototropin 1 & 2 (PHOT1/PHOT2)  leads to closing of stomata

e.) Starch content in the guard cell decreases during closing of stomata at the end of the day

Which of the following given statements will be correct for closing of stomata?