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#Question id: 15619


Wild type E. coli metabolizes the sugar lactose by expressing the enzyme ß-galactosidase. You have isolated a mutant that you call lac1–, which cannot synthesize ß-galactosidase and cannot grow on lactose (Lac–). During an condition isolate a mutation that constitutively expresses abnormally high levels of ßgalactosidase, which you designate lacc. Preliminary P1 transduction experiments indicate that lacc  is linked to the Tn5 insertion.  To map lacc  relative to lac1– you set up two reciprocal crosses. In the first cross you grow P1 on a strain that carries the Tn5 insertion and the lac1– mutation. You then use this lysate to infect a lacc mutant and select for Kanr. From 100 Kanr transductants examined, 20 are Lac–, 76 express ß-galactosidase constitutively and 4 show normal ß-galactosidase expression. In the second cross you grow P1 on a strain that carries the Tn5 insertion and the lacc mutation. You then use this lysate to infect a lac1– mutant, and select for Kanr. From 100 Kanr transductants examined, 81 are Lac– and 19  express ß-galactosidase constitutively. So what will be the correct order of  the Tn5 insertion and the lac1– and lacc  mutations. Express any measured distances as cotransduction frequencies.

#Unit 13. Methods in Biology
  1. The correct order will be Tn5- lac1--lacc, Tn5 to lac1- distance is 24%  while Tn5 to lacc  distance is 18%.
  2. The correct order will be Tn5- lacc-lac1-, Tn5 to lac1- distance is 18%  while Tn5 to lacc  distance is 24%.
  3. The correct order will be lac1--Tn5-lacc, Tn5 to lac1- distance is 24%  while Tn5 to lacc  distance is 18%
  4.  The correct order will be Tn5- lac1--lacc, Tn5 to lac1- distance is 14%  while Tn5 to lacc  distance is 18%
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TLS Online TPP Program

#Question id: 12169

#Unit 8. Inheritance Biology

During the phenotypic variations, the genotype shows variation at different effect given in graph;


According to the graph , this is an example of,

TLS Online TPP Program

#Question id: 12170

#Unit 8. Inheritance Biology

Sex determination in the grasshoppers is X-linked, if the cross is made between the heterozygous red phenotypic  female with the heterogametic red phenotypic male , then what will be the ratio of male and female with the red phenotype in F1 generation?

TLS Online TPP Program

#Question id: 12171

#Unit 8. Inheritance Biology

In the case of recessive lethal, showing lethality with X^w.  If the female grasshopper  with the genotype (X^+ X^w) is cross with the male grasshopper with the genotype (X^+O) , then what will be the probability of showing lethality in male and female?

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#Question id: 12172

#Unit 8. Inheritance Biology

In haplodiploid condition, hymnoptera  insects  female mates with a single male , find the mean genetic relatedness of;
i) the females in the progeny are related to,
ii) the males in the progeny are related to,

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#Question id: 12173

#Unit 8. Inheritance Biology

Female with only one X chromosome is a characteristics of individual with

TLS Online TPP Program

#Question id: 12174

#Unit 8. Inheritance Biology

Red-eyed female (X ^+X^+ ) crossed with white-eyed male (X^w Y) , all the F1 progeny shows the red phenotype, then what will be the probability of F2 phenotype;
 i)  Male with red eye phenotype
ii) Female with white eye phenotype
iii) Female with red eye phenotype
iv) Male with white eye phenotype