#Question id: 4772
#Unit 8. Inheritance Biology
A black Labrador, Three phenotype of black, brown and yellow is control by non allelic gene interaction. Following some genotype
The following conclusions were made
A. The 9:3:4 ratio obtained upon selfing of AaBb here indicates recessive epistasis
B. This is a recessive epistasis where homozygous bb is epistatic to A and a.
C. When Gene A and B incompletely link, It will be produced all phenotype black, brown and yellow upon selfing of AaBb
D. When Gene A and B incompletely link, test cross of AaBb will be produced all phenotype black, brown and yellow in ratio 1:1:2 respectively
Which of the following conclusions are correct?
#Question id: 27063
#Unit 1. Molecules and their Interaction Relevant to Biology
#Question id: 5781
#Unit 8. Inheritance Biology
A ____ mutation affects the phenotype only under certain conditions.
#Question id: 2982
#Unit 2. Cellular Organization
Match the following proteins (Column I) with their functions (Column II) during cell cycle.
|
Column I |
Column II |
|
A. Cdc25C phosphatase |
i. Activates vertebrate S phase CDKs |
|
B. INK4 |
ii. Activation of Mitotic CDKs |
|
C. Cdc25A phosphatase |
iii. Binds and inhibits G1 CDKs |
|
D. APC/CCdc20 |
iv. Degradation of securin |
#Question id: 2753
#Unit 2. Cellular Organization
DNA gyrase and topoisomerase IV are the targets of anti-bacterial drugs. Whereas type I and II are target of: