TLS Online TPP Program

#Question id: 3013


Bacteria survive adverse conditions by forming

#Unit 2. Cellular Organization
  1. zygotes.

  2. capsules.

  3. glycocalyx.

  4. endospores.

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TLS Online TPP Program

#Question id: 12616

#Unit 10. Ecological Principles

In the logistic equation
  
is a measure of the population's intrinsic rate of   increase. It is determined by which of the following?

TLS Online TPP Program

#Question id: 2867

#Unit 2. Cellular Organization

Deletion in region 3 enhances operon or rate of transcription (in trp operon); Choose an incorrect statement.

TLS Online TPP Program

#Question id: 4296

#Unit 3. Fundamental Processes

 Normally, a stop codon is required to release the ribosome from an mRNA but what happens to a ribosome that initiates translation of an mRNA fragment that lacks a termination codon. The Ribosome stalled at broken part of mRNA. In prokaryotic cells, such stalled ribosomes are rescued by the action of a chimeric RNA molecule that is part tRNA and part mRNA, appropriately called a tmRNA. What is sequence of events of this rescue process.

A. Translocation of the peptidyl-SsrA RNA results in the release of the broken mRNA

B. the SsrAAla–EF-Tu–GTP complex binds to the A-site of the ribosome and participates in the peptidyl transferase reaction

C. portion of the SsrA RNA acts as an mRNA and encodes 10 codons followed by a stop codon

D. the protein encoded by the incomplete mRNA is fused to a 10-amino-acid “peptide tag” at its carboxyl terminus, and the ribosome is recycled. Interestingly, the 10-amino-acid tag is recognized by cellular proteases that rapidly degrade the tag and the truncated polypeptide to which it is attached

TLS Online TPP Program

#Question id: 4096

#Unit 3. Fundamental Processes

The lambda repressor binds as a dimer to critical sites on the bacteriophage lambda genome to keep the lytic genes turned off, which allows the bacteriophage lambda genome to be maintained as a silent resident in the bacterial genome. Each molecule of the repressor consists of an N-terminal DNA-binding domain and a C-terminal dimerization domain. Upon induction (for example, by irradiation with ultraviolet light), the genes for lytic growth are expressed, bacteriophage lambda progeny are produced, and the bacterial cell lyses to release the viral progeny. Induction is initiated by cleavage of the lambda repressor at a site between the DNA-binding domain and the dimerization domain. In the absence of bound repressor, RNA polymerase initiates transcription of the lytic genes, triggering lytic growth.

A. Binding as monomers will be sufficiently weak that they do not compete with the binding of RNA polymerase. As a result, the genes for lytic growth will be turned on.

B. Binding as monomers will be sufficiently strong that they will compete with the binding of RNA polymerase. As a result, the genes for lysogenic growth will be turned on

C. The affinity of the dimeric lambda repressor for its binding site is the sum of all the interactions made by each DNA-binding domain. An individual DNA-binding domain will make just half the contacts and provide just half the binding energy as the dimer.

D. The affinity of the dimeric lambda repressor for its binding site is the sum of all the interactions made by each DNA-binding domain. An individual DNA-binding domain will make just double the contacts and provide just double the binding energy as the dimer.

Given that the number (concentration) of DNA-binding domains is unchanged by cleavage of the repressor, which of above outcomes will be possible?

TLS Online TPP Program

#Question id: 26891

#Unit 10. Ecological Principles

 A researcher working on island biogeography mapped how isolation-controlled immigration (I), and area-controlled extinction (E), will act on number of species present on the islands. He forgot to label the size of the islands (small or large) and the location of the islands (near or far) on the graph.
Using information from MacArthur and Wilson's equilibrium theory, select the option that correctly identifies A, B, C and D in the figure above.