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TLS Online TPP Program

#Question id: 368

Which of the following is true about the properties of aqueous solutions?

#Unit 1. Molecules and their Interaction Relevant to Biology

  1. A pH change from 5.0 to 6.0 reflects an increase in the hydroxide ion concentration (OH-) of 20%

  2. A pH change from 8.0 to 6.0 reflects an increase in the hydroxide ion concentration (OH-) by a factor of 100

  3. Hydrogen bonds form readily in aqueous solutions

  4. The pH can be calculated by adding 7 to the value of pOH

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TLS Online TPP Program

#Question id: 12499

#Unit 8. Inheritance Biology

On the basis of the linked marker genotypes II 3 can be told that:
TLS Online TPP Program

#Question id: 12500

#Unit 8. Inheritance Biology

In this pedigree II 1 is affected with an autosomal recessive disorder. The disease status for II 2, II 3 and II 4 is unknown. A and B represent alleles at a locus which is tightly linked to the disease locus with recombination fraction of 0. On the basis of the linked markers II 2 can be told that: 
TLS Online TPP Program

#Question id: 12501

#Unit 8. Inheritance Biology

In the pedigree shown, on the basis of the linked marker results II 3 can be told that:
TLS Online TPP Program

#Question id: 12502

#Unit 8. Inheritance Biology

In the pedigree shown, on the basis of the linked marker results II 4 can be told that:
TLS Online TPP Program

#Question id: 12503

#Unit 8. Inheritance Biology

In this pedigree II 1 is affected with an autosomal recessive disorder. The disease status for II 2 is unknown. A and B represent alleles at a locus which is tightly linked to the disease locus with recombination fraction of 0. Using the linked markers, II2 can be told that:
TLS Online TPP Program

#Question id: 12504

#Unit 8. Inheritance Biology

In this pedigree II 3 and III 1 are affected with an X-linked recessive disorder which is tightly linked to a marker locus with alleles A and B, with a recombination fraction of 0 between the disease and marker loci. Analysis of the linked marker results indicates that the disease must be segregating with: