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TLS Online TPP Program

#Question id: 12814

The difference between the length and breadth of a rectangle is 23m. If its perimeter is 206 m, then its area is

#General Aptitude
  1. 1520 m^2
  2. 2420 m^2
  3. 2480 m^2
  4. 2520 m^2
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TLS Online TPP Program

#Question id: 2159

#Unit 2. Cellular Organization

A channel protein
TLS Online TPP Program

#Question id: 15839

#Unit 8. Inheritance Biology

In the yeast cross of ade2 met14 his3 x + + +, a total of 120 tetrads are analyzed. The following tetrad types are found in the numbers shown below each tetrad. The markers ade2, met14, and his3 are abbreviated a, m, and h and the wild type allele of each gene is indicated by +.
 
Use this categorization and the numbers of each type to determine which (if any) of the three markers are linked. For any linked markers, calculate the distance between them in cM.      
To measure the distance between two linked His– mutations, you cross a his2– mutant to a his4– mutant and then dissect 100 tetrads. Your lab partner records which spore clones are His+ and which are His– ; but then the fool loses the papers on which most of the data is recorded. In the end all he can remember is that there were three different tetrad types an that there was only one tetrad of the type with 2 His+ and 2 His– spore clones.
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#Question id: 2963

#Unit 2. Cellular Organization

Eukaryotic chromosomes are composed of which of the following macromolecules?
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#Question id: 4096

#Unit 3. Fundamental Processes

The lambda repressor binds as a dimer to critical sites on the bacteriophage lambda genome to keep the lytic genes turned off, which allows the bacteriophage lambda genome to be maintained as a silent resident in the bacterial genome. Each molecule of the repressor consists of an N-terminal DNA-binding domain and a C-terminal dimerization domain. Upon induction (for example, by irradiation with ultraviolet light), the genes for lytic growth are expressed, bacteriophage lambda progeny are produced, and the bacterial cell lyses to release the viral progeny. Induction is initiated by cleavage of the lambda repressor at a site between the DNA-binding domain and the dimerization domain. In the absence of bound repressor, RNA polymerase initiates transcription of the lytic genes, triggering lytic growth.

A. Binding as monomers will be sufficiently weak that they do not compete with the binding of RNA polymerase. As a result, the genes for lytic growth will be turned on.

B. Binding as monomers will be sufficiently strong that they will compete with the binding of RNA polymerase. As a result, the genes for lysogenic growth will be turned on

C. The affinity of the dimeric lambda repressor for its binding site is the sum of all the interactions made by each DNA-binding domain. An individual DNA-binding domain will make just half the contacts and provide just half the binding energy as the dimer.

D. The affinity of the dimeric lambda repressor for its binding site is the sum of all the interactions made by each DNA-binding domain. An individual DNA-binding domain will make just double the contacts and provide just double the binding energy as the dimer.

Given that the number (concentration) of DNA-binding domains is unchanged by cleavage of the repressor, which of above outcomes will be possible?
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#Question id: 18816

#Unit 13. Methods in Biology

The PCR technique used to preferentially amplify only one strand of the target DNA by using unequal primer concentration is