TLS Online TPP Program

#Question id: 4737


Two independent pure line varieties having white and green phenotype in their fruit were cross, the all f1 progeny is white fruit. The F2 progeny obtain from selfing show white, yellow and green in ratio of 12:3:1. Which of the following is correct?

#Part-A Aptitude & General Biotechnology
  1. This is an incomplete dominance 

  2. This is example of supplementary gene interaction 

  3. These is two gene showing dependent assortment

  4. This is example of dominant epistasis

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TLS Online TPP Program

#Question id: 14259

#Part-B Specialized Branches in Biotechnology

C. roseus cells immobilized in Ca-alginate beads of diameter 0.5 mm are used for production of indole alkaloids (IA) in a fluidized-bed bioreactor. The rate limiting nutrient is glucose and no intraparticle diffusion limitations exist. Use the following data: Flow rate of the feed: Q = 1 l/h, Glucose in the feed: So = 30 g/l, Plant Cell Concentration: X = 6 g/l reac. The rate constant for IA formation: k = 5 d-1 (g/l)^-1 Ks = 0.4 g/l, Column diameter: Do = 0.15 m. Growth is negligible and Monod kinetics is valid. For 95% glucose conversion determine volume. 

TLS Online TPP Program

#Question id: 14260

#Part-B Specialized Branches in Biotechnology

C. roseus cells immobilized in Ca-alginate beads of diameter 0.5 mm are used for production of indole alkaloids (IA) in a fluidized-bed bioreactor. The rate limiting nutrient is glucose and no intraparticle diffusion limitations exist. Use the following data: Flow rate of the feed: Q = 1 l/h, Glucose in the feed: So = 30 g/l, Plant Cell Concentration: X = 6 g/l reac. The rate constant for IA formation: k = 5 d-1 (g/l)^-1 Ks = 0.4 g/l, Column diameter: Do = 0.15 m. Growth is negligible and Monod kinetics is valid. For 95% glucose conversion determine height of the column 

TLS Online TPP Program

#Question id: 14268

#Part-B Specialized Branches in Biotechnology

An activated-sludge waste treatment system is required to reduce the amount of BOD5 from 1000 mg/l to 20 mg/l at the exit. The sedimentation unit concentrates biomass by a factor of 3. Kinetic parameters are µm = 0.2 h-1 , Ks = 80 mg/l, kd = 0.01 h-1 , and Y M X/S = 0.5 g MLVSS/g BOD5. The flow of waste water is 10000 l/h and the size of the treatment basin is 50,000 l. What is the value of the solids residence time?

TLS Online TPP Program

#Question id: 14272

#Part-B Specialized Branches in Biotechnology

Penicillin is produced by P. chrysogenum in a fed-batch culture with the intermittent addition of glucose solution to the culture medium. The initial culture volume at quasi-steady state is V0 = 500 l, and glucose-containing nutrient solution is added with a flow rate of F = 50 l/h. Glucose concentration in the feed solution and initial cell concentration are S0 = 300 g/l and X0 = 20 g/l, respectively. The kinetic and yield coefficients of the organism are mm = 0.2 h-1 , KS = 0.5 g/l, and YX/S = 0.3 g dw/g glucose. If qP = 0.05 g product/g cells h and P0 = 0.1 g/l, determine the product concentration in the vessel at t = 10 h

TLS Online TPP Program

#Question id: 14278

#Part-B Specialized Branches in Biotechnology

Stirrer has a power number (Np) 10. If the stirrer speed (N) is 1s^-1, its diameter D=1m and the density of the medium is 1000 kg/m^3, the ungassed power input (P) in watts is