TLS Online TPP Program

#Question id: 2928


Which of the following S. pombe mutants is(are) larger than normal?

#Part-A Aptitude & General Biotechnology
  1. cdc2D

  2. cdc25−

  3.  wee1−

  4. cdc25− and wee1−

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TLS Online TPP Program

#Question id: 14160

#Part-B Specialized Branches in Biotechnology

In FASTA, For a Z-score > 15, the match can be considered extremely ______ with _____ of a homologous relationship.

TLS Online TPP Program

#Question id: 14160

#Part-A Aptitude & General Biotechnology

In FASTA, For a Z-score > 15, the match can be considered extremely ______ with _____ of a homologous relationship.

TLS Online TPP Program

#Question id: 14161

#Part-B Specialized Branches in Biotechnology

Which of the following is not a description of dynamic programming algorithm?

TLS Online TPP Program

#Question id: 14161

#Part-A Aptitude & General Biotechnology

Which of the following is not a description of dynamic programming algorithm?

TLS Online TPP Program

#Question id: 14164

#Part-B Specialized Branches in Biotechnology

Stoichiometric equations are used to represent growth of microorganisms provided a ' molecular formula' for the cells is available. The molecular formula for biomass is obtained by measuring the amounts of C, N, H, O and other elements in cells. For a particular bacterial strain, the molecular formula was determined to be C4.4H7.30 1.2N0.86 . These bacteria are grown under aerobic conditions with hexadecane (C16H34) as substrate. The reaction equation describing growth is:

                                  

  Assuming 100% conversion, what is the yield of cells from hexadecane in g g-l?   

TLS Online TPP Program

#Question id: 14165

#Part-B Specialized Branches in Biotechnology

Stoichiometric equations are used to represent growth of microorganisms provided a ' molecular formula' for the cells is available. The molecular formula for biomass is obtained by measuring the amounts of C, N, H, O and other elements in cells. For a particular bacterial strain, the molecular formula was determined to be C4.4H7.30 1.2N0.86 . These bacteria are grown under aerobic conditions with hexadecane (C16H34) as substrate. The reaction equation describing growth is:

                                    

Assuming 100% conversion, what is the yield of cells from oxygen in g g-l?