TLS Online TPP Program

#Question id: 14127


The most basic sequence alignment method is –

#Part-A Aptitude & General Biotechnology
  1. Dynamic programming 
  2. Scoring matrix 
  3. Dot plot
  4. None of the above 
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TLS Online TPP Program

#Question id: 11281

#Part-B Specialized Branches in Biotechnology

Owls eat rats, mice, shrews, and small birds. Assume that, over a period of time, an owl consumes 5,000 J of animal material. The owl loses 2,300 J in feces and owl pellets and uses 2,500 J for cellular respiration. What is the production efficiency of this owl?

TLS Online TPP Program

#Question id: 11281

#Part-B Specialized Branches in Biotechnology

Owls eat rats, mice, shrews, and small birds. Assume that, over a period of time, an owl consumes 5,000 J of animal material. The owl loses 2,300 J in feces and owl pellets and uses 2,500 J for cellular respiration. What is the production efficiency of this owl?

TLS Online TPP Program

#Question id: 11282

#Part-B Specialized Branches in Biotechnology

Which of the following ecosystems would likely have the largest net primary productivity per hectare and why?

TLS Online TPP Program

#Question id: 11282

#Part-B Specialized Branches in Biotechnology

Which of the following ecosystems would likely have the largest net primary productivity per hectare and why?

TLS Online TPP Program

#Question id: 11283

#Part-B Specialized Branches in Biotechnology

Herbivore ingests plant material with 1000 k j energy form producer and assimilated only 200 k J energy in their blood stream; additionally herbivore invests 120 k j energy in their maintenance. What is production efficiency of that herbivore?

TLS Online TPP Program

#Question id: 11284

#Part-B Specialized Branches in Biotechnology

Which of the following could qualify as a top-down control on a grassland community?