TLS Online TPP Program

#Question id: 14260


C. roseus cells immobilized in Ca-alginate beads of diameter 0.5 mm are used for production of indole alkaloids (IA) in a fluidized-bed bioreactor. The rate limiting nutrient is glucose and no intraparticle diffusion limitations exist. Use the following data: Flow rate of the feed: Q = 1 l/h, Glucose in the feed: So = 30 g/l, Plant Cell Concentration: X = 6 g/l reac. The rate constant for IA formation: k = 5 d-1 (g/l)^-1 Ks = 0.4 g/l, Column diameter: Do = 0.15 m. Growth is negligible and Monod kinetics is valid. For 95% glucose conversion determine height of the column 

#Section 5: Bioprocess Engineering and Process Biotechnology
  1. 3.21m    
  2. 1.95m  
  3. 1.17m
  4. 2.35m
More Questions
TLS Online TPP Program

#Question id: 14157

#Section 7: Recombinant DNA technology and Other Tools in Biotechnology

A ktup is composed of ___residues for protein sequences and _____ residues for DNA sequences.

TLS Online TPP Program

#Question id: 14158

#Section 7: Recombinant DNA technology and Other Tools in Biotechnology

BLAST uses a _______ to find matching words, whereas FASTA identifies identical matching words using the _____

TLS Online TPP Program

#Question id: 14159

#Section 7: Recombinant DNA technology and Other Tools in Biotechnology

Which of the following statement is not a benefit of FASTA over BLAST?

TLS Online TPP Program

#Question id: 14160

#Section 7: Recombinant DNA technology and Other Tools in Biotechnology

In FASTA, For a Z-score > 15, the match can be considered extremely ______ with _____ of a homologous relationship.

TLS Online TPP Program

#Question id: 14161

#Section 7: Recombinant DNA technology and Other Tools in Biotechnology

Which of the following is not a description of dynamic programming algorithm?

TLS Online TPP Program

#Question id: 14162

#Section 4: Fundamentals of Biological Engineering

A continuous process is set up for treatment of wastewater. Each day, 105 kg cellulose and 103 kg bacteria enter in the feed stream, while 104 kg cellulose and 1.5 x 104 kg bacteria leave in the effluent. The rate of cellulose digestion by the bacteria is 7 x 104 kg d-1. The rate of bacterial growth is 2 x 104 kg d-1 ; the rate of cell death by lysis is 5 x 102 kg d-1. Write balances for cellulose and bacteria in the system.