TLS Online TPP Program

#Question id: 629


In the presence of a fixed concentration of a competitive inhibitor, which of the following would best characterize an enzyme-catalyzed reaction when the concentration of the substrate is increased?

#Section 2: General Biology
  1. The inhibition does not change.

  2. The inhibition decreases.

  3. The Km increases.

  4. The maximal rate of reaction (V max) increases.

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TLS Online TPP Program

#Question id: 14254

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  Determine the height of the packed bed for 95% glucose conversion. Bed diameter is D0 = 0.2 m. Neglect the growth of the hybridomas and assume first order kinetics. 

TLS Online TPP Program

#Question id: 14255

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  If Yp/s is 4 mg Mab/g glu, determine the effluent Mab concentration of the system?

TLS Online TPP Program

#Question id: 14256

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  If Yp/s is 4 mg Mab/g glu, determine productivity of the system? __________________

TLS Online TPP Program

#Question id: 14257

#Section 5: Bioprocess Engineering and Process Biotechnology

The kLa of a small bubble column (2 l) has been measured as 20 h-1 at an airflow of 4 l/m in. If the rate of oxygen uptake by a culture of Catharanthus roseus is 0.2 mmol O2/g dry weight-h and if the critical oxygen concentration must be above 10% of saturation (about 8 mg/l), what is the maximum concentration of cells that can be maintained in the reactor?

TLS Online TPP Program

#Question id: 14258

#Section 5: Bioprocess Engineering and Process Biotechnology

C. roseus cells immobilized in Ca-alginate beads of diameter 0.5 mm are used for production of indole alkaloids (IA) in a fluidized-bed bioreactor. The rate limiting nutrient is glucose and no intraparticle diffusion limitations exist. Use the following data: Flow rate of the feed: Q = 1 l/h, Glucose in the feed: So = 30 g/l, Plant Cell Concentration: X = 6 g/l reac. The rate constant for IA formation: k = 5 d-1 (g/l)-1 Ks = 0.4 g/l, Column diameter: Do = 0.15 m. Growth is negligible and Monod kinetics is valid. For 95% glucose conversion determine required hydraulic residence time.

TLS Online TPP Program

#Question id: 14259

#Section 5: Bioprocess Engineering and Process Biotechnology

C. roseus cells immobilized in Ca-alginate beads of diameter 0.5 mm are used for production of indole alkaloids (IA) in a fluidized-bed bioreactor. The rate limiting nutrient is glucose and no intraparticle diffusion limitations exist. Use the following data: Flow rate of the feed: Q = 1 l/h, Glucose in the feed: So = 30 g/l, Plant Cell Concentration: X = 6 g/l reac. The rate constant for IA formation: k = 5 d-1 (g/l)^-1 Ks = 0.4 g/l, Column diameter: Do = 0.15 m. Growth is negligible and Monod kinetics is valid. For 95% glucose conversion determine volume.