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#Question id: 1831


The pyrogenic streptococcal exotoxins SPE, A, B, and H:

#Section 2: General Biology
  1. Are M proteins

  2. Cause post-streptococcal autoimmune disease

  3. Produce high titers of anti-streptolysin O

  4. Are superantigen

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#Question id: 3577

#Section 3: Genetics, Cellular and Molecular Biology

Which is the most correct description of a dominant trait?

TLS Online TPP Program

#Question id: 3578

#Section 3: Genetics, Cellular and Molecular Biology

A locus is:

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#Question id: 3579

#Section 3: Genetics, Cellular and Molecular Biology

Following some statement is correct with monohybrid and Dihybrid cross?

A) Two alleles for gene segregate into gametes in equal proportions.

B) Monohybrid F2 phenotype 1:2:1 ratio conclude, there is no segregation in character

C)  Monohybrid F2 phenotype 3:1 ratio conclude, there is a no blending inheritance

D) Dihybrid F 2 phenotype 3:1 ratio conclude complete linkage

TLS Online TPP Program

#Question id: 3580

#Section 2: General Biology

Different genetic cross regarding two independently assorting non allelic gene with complete dominance and their phenotypic ratio showed in a following. Which of the following is incorrect combination? 

Genetic cross

Phenotype ratio

1

AABb X AaBb

3:1

2

Aabb X  AaBb   

3:1:3:1

3

AABb X AaBB   

1:1 

4

Aabb X aaBb   

1:1:1:1

TLS Online TPP Program

#Question id: 3580

#Section 3: Genetics, Cellular and Molecular Biology

Different genetic cross regarding two independently assorting non allelic gene with complete dominance and their phenotypic ratio showed in a following. Which of the following is incorrect combination? 

Genetic cross

Phenotype ratio

1

AABb X AaBb

3:1

2

Aabb X  AaBb   

3:1:3:1

3

AABb X AaBB   

1:1 

4

Aabb X aaBb   

1:1:1:1

TLS Online TPP Program

#Question id: 3581

#Section 2: General Biology

What is the probability that each of the following pairs of parents will produce the indicated offspring? (Assume independent assortment of all gene pairs.)

(a) AABBCc X  aabbcc → AaBbCc          (b) AABbCc  X AaBbCc → AAbbCC

(c) AaBbCc  X AaBbCc → AaBbCc         (d) aaBbCC  X  AABbcc → AaBbCc