TLS Online TPP Program

#Question id: 3628


Two mutant plants, both bearing white flowers, were crossed. All F1 plants had red colored flowers. Which one of the following conclusions is correct?

#Section 3: Genetics, Cellular and Molecular Biology
  1. The mutations in the parents do not complement each other

  2. The mutations in the parents are allelic

  3. The mutations in the parents are non-allelic

  4. The mutations in the parents are linked

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TLS Online TPP Program

#Question id: 28105

#Section 5: Bioprocess Engineering and Process Biotechnology

At 2000 K, one chemical reaction has 〖∆𝑮〗^°  = 6.12 kJ/mol. What is Keq for this reaction at the same temperature?

TLS Online TPP Program

#Question id: 28106

#Section 5: Bioprocess Engineering and Process Biotechnology

In case of a chemical reaction, if 〖∆𝑮〗^°>𝟎, then Keq is

TLS Online TPP Program

#Question id: 28107

#Section 5: Bioprocess Engineering and Process Biotechnology

If the equilibrium constant for a chemical reaction at 20° C is 20, the standard free energy change associated with the reaction will be (R=1.98 cal/mol/K):

TLS Online TPP Program

#Question id: 28108

#Section 5: Bioprocess Engineering and Process Biotechnology

Consider the following reversible reaction. In a 3.00 liter container, the following  amounts are found in equilibrium at 400 oC: 0.0420 mole N2, 0.516 mole H2 and 0.0357 mole NH3. Evaluate Keq.

N2(g) + 3H2(g) ↔ 2NH3(g)

TLS Online TPP Program

#Question id: 28109

#Section 5: Bioprocess Engineering and Process Biotechnology

If the equilibrium constant for the reaction
A + 2B ↔ C + 5/2 D
has a value of 4.0, what is the value of the equilibrium constant for the reaction
2C + 5D ↔ 2A + 4B
at the same temperature?

TLS Online TPP Program

#Question id: 28110

#Section 5: Bioprocess Engineering and Process Biotechnology

A certain reaction has a value of Keq = 0.0260 at 25 °C and ΔHrxn=32.4kJ/mol. Calculate the value of Keq at 37 °C.