TLS Online TPP Program

#Question id: 5241


Genes a, b, and c are widely spaced in the bacterial genome. Transducing phage from an a+ b+ c+ bacterium were used to infect a culture of a- b- c- cells, and b+ transductants were selected. Which of the following best describes the predicted genotypes of these transductants?

#Section 3: Genetics, Cellular and Molecular Biology
  1. Mostly ab+ c-           

  2. Mostly ab+ c+      

  3. Mostly a+ b+ c+          

  4. Mostly a+ b+ c-

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TLS Online TPP Program

#Question id: 16826

#Section 1: Engineering Mathematics

Only one of the real roots of f(x) = x6 - x - 1 lies in the interval 1 x 2 and bisection method is used to find its value. For achieving an accuracy of 0.001, the required minimum number of iterations is  

TLS Online TPP Program

#Question id: 14313

#Section 5: Bioprocess Engineering and Process Biotechnology

An industrial waste-water stream is fed to a stirred-tank reactor continuously and the cells are recycled back to the reactor from the bottom of the sedimentation tank placed after the reactor. The following are given for the system: F = 100 l/h; S0 = 5000 mg/l; mm = 0.25 h-1 ; Ks = 200 mg/l; α (recycle ratio) = 0.6; C (cell concentration factor) = 2; Y M X/S = 0.4. The effluent concentration is desired to be 100 mg/l.  Determine the cell concentration in the reactor and in the recycle stream.

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TLS Online TPP Program

#Question id: 12922

#Section 7: Recombinant DNA technology and Other Tools in Biotechnology

 Match the following:-
1. Ligase chain reaction.              i. Mutation detection
2. Nucleic acid sequence based   amplification.                            ii.Non isothermal                   
3. Loop mediated isothermal amplification.                      iii. Viral detection
4. Branched DNA amplification.   iv.parasitic disease

TLS Online TPP Program

#Question id: 1840

#Section 2: General Biology

What does the term variolation refer to?

TLS Online TPP Program

#Question id: 14920

#Section 1: Engineering Mathematics

The function f(c) = x5 - 5x4+5x3 - 1 has