To express a yeast gene in E. coli, your task is to design a strategy to insert the yeast gene into the bacterial plasmid. Below is a map of the area of the yeast genome surrounding the gene in which you are interested.

 

The distance between each tick mark placed on the line above is 100 bases in length

Below are the enzymes you can use, with their specific cut sites shown 5’-XXXXXX-3’ 3’-XXXXXX-5’

 

The plasmid is 5,000 bases long and the two farthest restriction enzyme sites are 200 bases apart. The plasmid has an ampicillin resistance gene somewhere on the plasmid distal from the restriction cut sites.

                              

Which of the following restriction enzyme is the best choice for you use to design a way to get the insert into the vector?

#Question id: 14321

#Section 5: Bioprocess Engineering and Process Biotechnology

Both Saccharomyces cerevisiae yeast and Zymomonas mobilis bacteria produce ethanol from glucose under anaerobic conditions without external electron acceptors. The biomass yield from glucose is 0.11 g g-1 for yeast and 0.05 g g-I for Z. mobilis. In both cases the nitrogen source is NH 3. Both cell compositions are represented by the formula CH 1.800.5N0.2. Compare actual yield with theoretical maximum for Zymomonas mobilis bacteria ?

#Question id: 14322

#Section 5: Bioprocess Engineering and Process Biotechnology

Production of recombinant protein by a geneticallyengineered strain of Escherichia coli is proportional to cell growth. Ammonia is used as nitrogen source for aerobic respiration of glucose. The recombinant protein has an overall formula CH_I.550_0.31N_0.25. The yield ofbiomass from glucose is measured at 0.48 g g^-1; the yield of recombinant protein from glucose is about 20% that for cells. How much ammonia is required per gmol glucose?

#Question id: 14323

#Section 5: Bioprocess Engineering and Process Biotechnology

Production of recombinant protein by a geneticallyengineered strain of Escherichia coli is proportional to cell growth. Ammonia is used as nitrogen source for aerobic respiration of glucose. The recombinant protein has an overall formula CHI.5500.31N0.25. The yield ofbiomass from glucose is measured at 0.48 g g-1; the yield of recombinant protein from glucose is about 20% that for cells. What is the oxygen demand per gmol glucose?

#Question id: 14324

#Section 5: Bioprocess Engineering and Process Biotechnology

Production of recombinant protein by a geneticallyengineered strain of Escherichia coli is proportional to cell growth. Ammonia is used as nitrogen source for aerobic respiration of glucose. The recombinant protein has an overall formula CHI.5500.31N0.25. The yield of biomass from glucose is measured at 0.48 g g^-1; the yield of recombinant protein from glucose is about 20% that for cells. If the biomass yield remains at 0.48 g g^{- l}, how much change in oxygen requirement for wild-type E. coli unable to synthesise recombinant protein?

#Question id: 14325

#Section 5: Bioprocess Engineering and Process Biotechnology

Production of recombinant protein by a geneticallyengineered strain of Escherichia coli is proportional to cell growth. Ammonia is used as nitrogen source for aerobic respiration of glucose. The recombinant protein has an overall formula CHI.5500.31N0.25. The yield ofbiomass from glucose is measured at 0.48 g g-1; the yield of recombinant protein from glucose is about 20% that for cells. If the biomass yield remains at 0.48 g g- l, how much change in ammonia requirement for wild-type E. coliunable to synthesise recombinant protein?