Practice Questions

TLS Online TPP Program

#Question id: 397

The loss of water from a plant by transpiration cools the leaf. Movement of water in transpiration requires both adhesion to the conducting walls and wood fibers of the plant and cohesion of the molecules to each other. A scientist wanted to increase the rate of transpiration of a crop species to extend its range into warmer climates. The scientist substituted a nonpolar solution with an atomic mass similar to that of water for hydrating the plants. What do you expect the scientist's data will indicate from this experiment?

#Section 4: Fundamentals of Biological Engineering

The rate of transpiration will be the same for both water and the nonpolar substance.
The rate of transpiration will be slightly lower with the nonpolar substance as the plant will not have evolved with the nonpolar compound.
Transpiration rates will fall to zero as nonpolar compounds do not have the properties necessary for adhesion and cohesion.
Transpiration rates will increase as nonpolar compounds undergo adhesion and cohesion with wood fibers more readily than water.

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TLS Online TPP Program

#Question id: 14393

#Section 1: Engineering Mathematics

If the system of equations 2x + 3y + 5 = 0, x + ky + 5 = 0, kx — 12y — 14 = 0 has non-trivial solution, then the value of k is

TLS Online TPP Program

#Question id: 14394

#Section 5: Bioprocess Engineering and Process Biotechnology

1.0 timol of an enzyme that contains five active sites per molecule converts 1.0 pmol substrate every 2 microseconds. Calculate catalytic centre activity (sec^-1). ......10^5

TLS Online TPP Program

#Question id: 14395

#Section 5: Bioprocess Engineering and Process Biotechnology

An enzyme is available at a specific activity of 500 units/mg protein. For an assay, 10miro mole substrate need to be converted per minute. What mass (in mg) of protein would you take for this to be achieved?

TLS Online TPP Program

#Question id: 14396

#Section 5: Bioprocess Engineering and Process Biotechnology

A purified hydrolytic enzyme (Mr 150 000) is available with the description: Gives a Vmax of 3 200 units/mg protein under optimal conditions. How many micromoles of substrate can be hydrolysed by 1 mg of protein in 1 minute

TLS Online TPP Program

#Question id: 14397

#Section 5: Bioprocess Engineering and Process Biotechnology

A purified hydrolytic enzyme (Mr 150 000) is available with the description: Gives a Vmax of 3 200 units/mg protein under optimal conditions. How many nmol of enzyme are there in 1 mg