TLS Online TPP Program

#Question id: 16007


What is the effect of excess accumulation of metabolite products (lactate and ammonium) on cells?

#Section 6: Plant, Animal and Microbial Biotechnology
  1. They act as growth promoters
  2. They act as growth inhibitors
  3. Have no effect on cells
  4. Lactate helps in the growth while ammonium inhibits the growth
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TLS Online TPP Program

#Question id: 14306

#Section 5: Bioprocess Engineering and Process Biotechnology

Pseudomonas putida with mm = 0.5 h-1 is cultivated in a continuous culture under aerobic conditions where D = 0.28 h-1 . The carbon and energy source in the feed is lactose with aconcentration of S0 = 2 g/l. The effluent lactose concentration is desired to be S = 0.1 g/l. If the growth rate is limited by oxygen transfer, by using the following information:

Determine the steady-state biomass concentration (X)

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TLS Online TPP Program

#Question id: 14307

#Section 5: Bioprocess Engineering and Process Biotechnology

Pseudomonas putida with mm = 0.5 h-1 is cultivated in a continuous culture under aerobic conditions where D = 0.28 h-1 . The carbon and energy source in the feed is lactose with aconcentration of S0 = 2 g/l. The effluent lactose concentration is desired to be S = 0.1 g/l. If the growth rate is limited by oxygen transfer, by using the following information


Determine specific rate of oxygen consumption (qO2 ).

TLS Online TPP Program

#Question id: 14308

#Section 5: Bioprocess Engineering and Process Biotechnology

Pseudomonas putida with µm = 0.5 h-1 is cultivated in a continuous culture under aerobic conditions where D = 0.28 h-1 . The carbon and energy source in the feed is lactose with aconcentration of S0 = 2 g/l. The effluent lactose concentration is desired to be S = 0.1 g/l. If the growth rate is limited by oxygen transfer, by using the following information:


What should be the oxygen-transfer coefficient (kLa) in order to overcome oxygentransfer limitation (i.e., CL = 2 mg/l)? ___________________

TLS Online TPP Program

#Question id: 14309

#Section 5: Bioprocess Engineering and Process Biotechnology

Glucose is converted to ethanol by immobilized yeast cells entrapped in gel beads. The specific rate of ethanol production is: qP = 0.2 g ethanol/g-cell-h. The effectiveness factor for an average bead is 0.8. Each bead contains 50 g/L of cells. The voids volume in the column is 40%. Assume growth is negligible (all glucose is converted into ethanol). The feed flow rate is F = 400 l/h and glucose concentration in the feed is S0i = 150 g glucose/l. The diameter of the column is 1 m and the yield coefficient is about 0.49 g ethanol/g glucose. The column height is 4 m. What is the glucose conversion at the exit of the column?

TLS Online TPP Program

#Question id: 14310

#Section 5: Bioprocess Engineering and Process Biotechnology

Glucose is converted to ethanol by immobilized yeast cells entrapped in gel beads. The specific rate of ethanol production is: qP = 0.2 g ethanol/g-cell-h. The effectiveness factor for an average bead is 0.8. Each bead contains 50 g/L of cells. The voids volume in the column is 40%. Assume growth is negligible (all glucose is converted into ethanol). The feed flow rate is F = 400 l/h and glucose concentration in the feed is S0i = 150 g glucose/l. The diameter of the column is 1 m and the yield coefficient is about 0.49 g ethanol/g glucose. The column height is 4 m. What is the ethanol concentration in the exit stream?

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TLS Online TPP Program

#Question id: 14311

#Section 5: Bioprocess Engineering and Process Biotechnology

Consider following fig, which applies to a fed-batch system.

                           

Assume at t = 0, V = 100 l, X = 2 g/l, m = 1 h-1 , S0 = 4 g/l, and S = 0.01 g/l. V is increased at a constant rate such that dV/dt = 20 l/h = F (or flow rate) and X is constant at all times. What is µ at t = 5 h?