TLS Online TPP Program

#Question id: 18687


Homology modeling involves 

#Section 7: Recombinant DNA technology and Other Tools in Biotechnology
  1. Alignment of the target sequence to the sequence  of a template structure 
  2. Alignment of the target sequence with multiple sequences with no structural information 
  3. ab initio structure prediction 
  4. No input of sequence information 
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TLS Online TPP Program

#Question id: 604

#Section 2: General Biology

An enzyme is irreversibly inhibited by diisopropylfluorophosphate (DFP). What does this show?

TLS Online TPP Program

#Question id: 12992

#Section 2: General Biology

α-helix changes its configurations according to the environment then
a. membrane encompassing α-helix have nonpolar residue oriented toward the membrane lipid.
b. if α-helix is found in plasm then polar residue will be oriented toward the outside.
c. if α-helix is found in plasm then nonpolar residue will be present inside the core.
d.  membrane encompassing α-helix have polar residue oriented towards the membrane lipid.
Choose incorrect statement

TLS Online TPP Program

#Question id: 15375

#Section 1: Engineering Mathematics

F(s) is the Laplace transform of the function
f(t) = 2t2e-t   F (1) is ......   (correct to two decimal places) 

TLS Online TPP Program

#Question id: 14162

#Section 5: Bioprocess Engineering and Process Biotechnology

A continuous process is set up for treatment of wastewater. Each day, 105 kg cellulose and 103 kg bacteria enter in the feed stream, while 104 kg cellulose and 1.5 x 104 kg bacteria leave in the effluent. The rate of cellulose digestion by the bacteria is 7 x 104 kg d-1. The rate of bacterial growth is 2 x 104 kg d-1 ; the rate of cell death by lysis is 5 x 102 kg d-1. Write balances for cellulose and bacteria in the system.

TLS Online TPP Program

#Question id: 3587

#Section 3: Genetics, Cellular and Molecular Biology

Short hair in rabbits (S) is dominant over long hair (s). The following crosses are carried out, producing the progeny shown.

A. short X short = Progeny ( 3 short and 1 long)

B- short  X long = Progeny  (1 short and 1 long )

What is possible genotypes of the parents of  cross A and cross B respectively