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TLS Online TPP Program

#Question id: 15697

Which of the following does not describe PAM matrices?

#SCPH05 I Biotechnology
  1. These matrices are used in optimal alignment scoring
  2. It stands for Point Altered Mutations
  3. It stands for Point Accepted Mutations
  4. It was first developed by Margaret Dayhoff
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TLS Online TPP Program

#Question id: 22946

#SCPH01 Biochemistry

FLOWERING LOCUS C (Floral repressor) that is expressed in Leaves and apex, belongs to which, transcription factor family
TLS Online TPP Program

#Question id: 18375

#SCPH01 Biochemistry

What is the function of Siderophores secreted by bacteria
TLS Online TPP Program

#Question id: 18702

#SCPH01 Biochemistry

What would be the effect on the PCR reaction if any of the following circumstances arose: 1) there are no primers in the reaction, 2) there are no dNTPs in the reaction, 3) there is no Taq polymerase in the reaction?
TLS Online TPP Program

#Question id: 10286

#I Life Science/ Life Sciences Group – I-V

The enzyme aldolase, catalyzes a reversible aldol condensation, Fructose 1,6-bisphosphate is cleaved to yield two different triose phosphates, glyceraldehyde 3-phosphate, an aldose, and dihydroxyacetone phosphate, a ketose. There are two classes of aldolases such as;

A) Class I aldolases

B) Class II aldolases

i) Found in animals and plants

ii) Found in in fungi and bacteria

iii) formation of protonated Schiff base on enzyme and its active site contain lysine residue

iv) do not form the Schiff base intermediate and a zinc ion at the active site is coordinated with the carbonyl oxygen at C-2

In which of the following option is the given enzyme with its correct statements?
TLS Online TPP Program

#Question id: 15622

#SCPH01 Biochemistry

9 In your study of a new bacterial species you have identified a transducing phage that you call Px. In addition you have worked out methods to make random transposon insertions into the bacterial genome. You have generated two different transposon insertion collections one with 105 random Tn5 (Kanr) insertions and the other with 105 random Tn10 (Tetr) insertions. You grow Px phage on the mixed collection of Tn5 insertions and use the resulting phage lysate to infect the mixed collection of Tn10 insertions. You select 10,000 Kanr  transductants and find that 80 of them are Tets. Use this information to estimate the total size of the bacterial genome assuming that both Tn5 and Tn10 insert randomly and that the average size of a fragment recombined into the recipient genome during Px transduction is 55 kbp. (Tn5 is about 5 kbp and Tn10 is 10 kbp.)