A. Trypsin treated core histones quickly forms 30-nm fibers

B. Core histones lacking their amino-terminal tails are incapable of forming 30-nm fibers

C. Interaction between the positively charged amino terminus of histone H4 and a negatively charged region of the histone-fold domain of histone H2A is particularly important for 30-nm fiber formation

D. H2A that interact with the H4 tail are conserved across many eukaryotic organisms but are not involved in DNA binding or formation of the histone octamer.

Choose true and false

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#Question id: 7767

#Unit 5. Developmental Biology

How can evolution select for phenotypes that postpone reproduction or sexual maturity?” There is often a trade-off between reproduction and maintenance, and in many species reproduction and senescence are closely linked. Recent studies of mice, Caenorhabditis elegans, and Drosophila suggest that there is a conserved genetic pathway that regulates aging and that it can indeed be selected for. This pathway involves the response to insulin and insulin-like growth factors, Name of these transcription factors are

TLS Online TPP Program

#Question id: 33429

#Unit 1. Molecules and their Interaction Relevant to Biology

How many O₂ are involved in Palmitic acid oxidation

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#Question id: 19122

#Unit 8. Inheritance Biology

Trisomy 18 is one of the most common trisomies observed in human populations. You prepare DNA samples from two unrelated infants, both with trisomy 18, and from their parents. You then type the infants and their parents for four SSRs distributed along chromosome 18:

     

             

                                         

In which division of meiosis did nondisjunction occur in Family 2?

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#Question id: 4338

#Unit 3. Fundamental Processes

Altering patterns of gene expression in prokaryotes would most likely serve an organism's survival by __.

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#Question id: 17996

#Unit 8. Inheritance Biology

Consider a heritable autosomal disease with an incidence in the population of 1 per thousand. On average, individuals with the disease have 80% as many children as the population average. In answering the various parts of this question, assume that mating is random. Now assume that the mutation rate is zero, that the disease is recessive, and that the disease allele is maintained in the population by heterozygote advantage. Calculate the heterozygote advantage,