TLS Online TPP Program

#Question id: 2142


Glucose transport into erythrocytes is an example of

#Unit 2. Cellular Organization
  1. active transport.

  2. antiport.

  3. electrogenic uniport

  4. facilitated diffusion.

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TLS Online TPP Program

#Question id: 68

#Unit 1. Structure and Function of Biomolecules

Match the following functional groups given in column I with their respective representatives given in column II.

COLUMN ICOLUMN II
1. Anhydridea. RCOOR
2. Etherb. ROCOCH3
3. Acetylc. ROR
4. Amidod. RCOOCOR
5. Estere. RCONH2

TLS Online TPP Program

#Question id: 68

#Unit 1. Structure and Function of Biomolecules

Match the following functional groups given in column I with their respective representatives given in column II.

COLUMN ICOLUMN II
1. Anhydridea. RCOOR
2. Etherb. ROCOCH3
3. Acetylc. ROR
4. Amidod. RCOOCOR
5. Estere. RCONH2

TLS Online TPP Program

#Question id: 69

#Unit 1. Structure and Function of Biomolecules

Which of the following is the diastereomer of the following compound?

TLS Online TPP Program

#Question id: 70

#Unit 1. Structure and Function of Biomolecules

The dimensions of living cells are limited, on the lower end by the minimum number of biomolecules necessary for function, and on the upper end by the rate of diffusion of solutes such as oxygen. Except for highly elongated cells, they usually have lengths and diameters in the range of

TLS Online TPP Program

#Question id: 71

#Unit 1. Structure and Function of Biomolecules

Which of the following is not the priority rule for R, S Configuration?

TLS Online TPP Program

#Question id: 72

#Unit 1. Structure and Function of Biomolecules

For the reaction catalyzed by the enzyme hexokinase: Glucose + ATP → glucose 6-phosphate + ADP the equilibrium constant, Keq, is 7.8 × 102. In living E. coli cells, [ATP] = 5 mM, [ADP] = 0.5 mM, [glucose] = 2 mM, and [glucose 6-phosphate] = 1 mM. Which of the following conclusions made on the basis of the above calculations is incorrect?