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#Question id: 13145
#Unit 8. Inheritance Biology
We can construct a genetic map by considering the recombination frequencies for each pair of genes. The recombination frequency between a and b is 50%, a and c is 50%, and b and c is 20%. What will be the correct prediction about this statements;
a) Recombination frequency between genes a and b and gene a and c is expected with independent assortment
b) The genes a and b and gene a and c may either be on different chromosomes or be very far apart on the same chromosome; so we will place them in different linkage groups
c) The gene b and c are linked
d) The gene b and c are unlinked
Which of the following is the correct sequence?
TLS Online TPP Program
#Question id: 13146
#Unit 8. Inheritance Biology
Two gene A and B gene distance is 30 m.u. if the frequency of the given gametes is,
i) AaBb=0.70 ii) Aabb=0.30
What will be the correct prediction?
a) Genes a and b are linked in cis
b) A and B gene are independently assort
c) Gene a and b showing incomplete linkage
d) Genes a and b are linked in trans
TLS Online TPP Program
#Question id: 13147
#Unit 8. Inheritance Biology
A cross was made between pure Blue and long pollen length with white and short pollen length. The F1 were test crossed. The F2 progeny obtained was as follows:
The genetic distance (cM) between flower colour and pollen length is;
TLS Online TPP Program
#Question id: 13148
#Unit 8. Inheritance Biology
During a three point test cross is carried out. The parental cross was AABBCC X aabbcc , the F1 progeny is AaBbCc. What will be the no. of given genotype in 100 progeny?
i) AaBbCc ii) aaBbcc
TLS Online TPP Program
#Question id: 13149
#Unit 8. Inheritance Biology
A three point test cross was made between the st^+-e^+-ss^+ and st-e-ss , the genotype of the double cross over will be; st^+-e-ss^+ and st-e^+-ss. Based on this, determine the order of the genes.
TLS Online TPP Program
#Question id: 13150
#Unit 8. Inheritance Biology
A fruit fly Drosophila melanogaster showing three point test cross st+-e+-ss+ was crossed with triplet recessive mutant st-e-ss. The F1 hybrid was the backcross with the recessive mutant and the phenotype recorded as follows;
The distance in map unit (mu) between st+ to e+ and e+ to ss+ is