An activated-sludge waste treatment system is required to reduce the amount of BOD₅ from 1000 mg/l to 20 mg/l at the exit. The sedimentation unit concentrates biomass by a factor of 3. Kinetic parameters are µ_m = 0.2 h-1 , K_s = 80 mg/l, k_d = 0.01 h-1 , and Y ^M _X/S = 0.5 g MLVSS/g BOD₅. The flow of waste water is 10000 l/h and the size of the treatment basin is 50,000 l. What is the value of the solids residence time?

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#Question id: 18670

#Part-A Aptitude & General Biotechnology

Quantitative analysis i.e., measurements of the relative amounts of different proteins in a sample can be achieved by 

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#Question id: 18671

#Part-A Aptitude & General Biotechnology

larger fragments of DNA can be analysed by Agarose gel while shorter fragment 80 – 1000 nt can be analysed by using 

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#Question id: 18672

#Part-A Aptitude & General Biotechnology

Larger DNA fragments up to 2 × 10 ³ kb can be separated by using

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#Question id: 18673

#Part-A Aptitude & General Biotechnology

A person is suffering of bacterial food-borne illness from Salmonella infections which particularly useful in identifying the course of outbreaks

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#Question id: 18674

#Part-A Aptitude & General Biotechnology

Electrophoresis of normal RNA can be achieved by using

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#Question id: 18675

#Part-A Aptitude & General Biotechnology

Which of the following is the example free solution electrophoresis