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TLS Online TPP Program

#Question id: 14928

#Section 5: Bioprocess Engineering and Process Biotechnology

 Escherichia coli grows with a doubling time of 0.5 h in the exponential growth phase. What is the value of the specific growth rate? 

TLS Online TPP Program

#Question id: 14929

#Section 5: Bioprocess Engineering and Process Biotechnology

Escherichia coli grows with a doubling time of 0.5 h in the exponential growth phase. How much time would be required to grow the cell culture from 0.1 to 10 kgdry cell m^-3 

TLS Online TPP Program

#Question id: 14930

#Section 5: Bioprocess Engineering and Process Biotechnology

E. coli grows from 0.10 to 0.50 kg dry cell m^-3 in 1 h. Assuming exponential growth during this period, evaluate the specific growth rate 

TLS Online TPP Program

#Question id: 14931

#Section 5: Bioprocess Engineering and Process Biotechnology

E. coli grows from 0.10 to 0.50 kg dry cell m^-3 in 1 h. Evaluate the doubling time during the exponential growth phase 

TLS Online TPP Program

#Question id: 14932

#Section 5: Bioprocess Engineering and Process Biotechnology

 E. coli grows from 0.10 to 0.50 kg dry cell m^-3 in 1 h. How much time would be required to grow from 0.10 to 1.0 kg dry cell m^-3? You may assume exponential growth during this period 

TLS Online TPP Program

#Question id: 14933

#Section 5: Bioprocess Engineering and Process Biotechnology

E. coli was continuously cultured in a continuous stirred tank fermenter with a working volume of 1.0 I by chemostat. A medium containing 4.0 g1^-1 of glucose as a carbon source was fed to the fermenter at a constant flow rate of 0.5 I h^-1, and the glucose concentration in the output stream was 0.20 g1^-1, The cell yield with respect to glucose YxS was 0.42 g dry cells per gram glucose. Determine the cell concentration in the output stream