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#Question id: 15517


For the Ordinary Differential Equation , with initial conditions , the solution is dt 

#Section 1: Engineering Mathematics
  1. _5e2t  + 6e3t

  2. 5e2t = + 6e3t
  3. -10e2t + 10e3t 
  4. 10e2t +10e+3t 

Answer:- Option(s): 3


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