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TLS Online TPP Program

#Question id: 36357

Which of the following statements is/are correct about FindMod ? 

#Section 7: Recombinant DNA technology and Other Tools in Biotechnology
  1. FindMod is a subprogram that uses experimentally determined peptide fingerprint information.
  2. If a difference is found, it predicts a particular type of modification based on a set of predefined rules.
  3. It can predict 28  types of modifications, including methylation, phosphorylation, lipidation, and sulfation.
  4. It predicts the subcellular locations of eukaryotic proteins based on their N-terminal amino acid sequence only. 
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TLS Online TPP Program

#Question id: 14316

#Section 5: Bioprocess Engineering and Process Biotechnology

Cellulomonas bacteria used as single-cell protein for human or animal food are produced from glucose under anaerobic conditions. All carbon in the substrate is converted into biomass; ammonia is used as nitrogen source. The molecular formula for the biomass is CHI.5600.54N0.16; the cells also contain 5% ash. How does the yield of biomass from substrate in mass and molar terms compare with the maximum possible biomass yield?
TLS Online TPP Program

#Question id: 14317

#Section 5: Bioprocess Engineering and Process Biotechnology

system for manufacture of single-cell protein is Methylophilus methylotrophus. This organism is produced aerobically from methanol with ammonia as nitrogen source. The molecular formula for the biomass is CH 1.6800.36N0.22; these cells contain 6% ash. What is the maximum possible biomass yield from methanol?
TLS Online TPP Program

#Question id: 14318

#Section 5: Bioprocess Engineering and Process Biotechnology

system for manufacture of single-cell protein is Methylophilus methylotrophus. This organism is produced aerobically from methanol with ammonia as nitrogen source. The molecular formula for the biomass is CH 1.6800.36N0.22; these cells contain 6% ash. If the actual yield of biomass from methanol is 42% the thermodynamic maximum, what is the oxygen demand?
TLS Online TPP Program

#Question id: 14319

#Section 5: Bioprocess Engineering and Process Biotechnology

Both Saccharomyces cerevisiae yeast and Zymomonas mobilis bacteria produce ethanol from glucose under anaerobic conditions without external electron acceptors. The biomass yield from glucose is 0.11 g g-1 for yeast and 0.05 g g-I for Z. mobilis. In both cases the nitrogen source is NH3. Both cell compositions are represented by the formula CH1.800.5N0.2. What is the yield of ethanol from glucose by Saccharomyces cerevisiae yeast?
TLS Online TPP Program

#Question id: 14320

#Section 5: Bioprocess Engineering and Process Biotechnology

Both Saccharomyces cerevisiae yeast and Zymomonas mobilis bacteria produce ethanol from glucose under anaerobic conditions without external electron acceptors. The biomass yield from glucose is 0.11 g g-1 for yeast and 0.05 g g-I for Z. mobilis. In both cases the nitrogen source is NH 3. Both cell compositions are represented by the formula CH 1.800.5N0.2. What is the yield of ethanol from glucose by Zymomonas mobilis bacteria?

TLS Online TPP Program

#Question id: 14321

#Section 5: Bioprocess Engineering and Process Biotechnology

Both Saccharomyces cerevisiae yeast and Zymomonas mobilis bacteria produce ethanol from glucose under anaerobic conditions without external electron acceptors. The biomass yield from glucose is 0.11 g g-1 for yeast and 0.05 g g-I for Z. mobilis. In both cases the nitrogen source is NH 3. Both cell compositions are represented by the formula CH 1.800.5N0.2. Compare actual yield with theoretical maximum for Zymomonas mobilis bacteria ?