The steady state assumption, as applied to enzyme kinetics, implies:

TLS Online TPP Program

#Question id: 14251

#Section 5: Bioprocess Engineering and Process Biotechnology

Yeast cells are recovered from a fermentation broth by using a tubular centrifuge. Sixty percent (60%) of the cells are recovered at a flow rate of 12 l/min with a rotational speed of 4000 rpm. Recovery is inversely proportional to flow rate. a. To increase the recovery of cells to 95% at the same flow rate, what should be the rpm of the centrifuge?

____________________

TLS Online TPP Program

#Question id: 14252

#Section 5: Bioprocess Engineering and Process Biotechnology

Yeast cells are recovered from a fermentation broth by using a tubular centrifuge. Sixty percent (60%) of the cells are recovered at a flow rate of 12 l/min with a rotational speed of 4000 rpm. Recovery is inversely proportional to flow rate. At a constant rpm of 4000 rpm, what should be the flow rate to result in 95% cell recovery?

________________-

TLS Online TPP Program

#Question id: 14253

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  Determine the volume of the packed bed for 95% glucose conversion. Bed diameter is D0 = 0.2 m. Neglect the growth of the hybridomas and assume first order kinetics. 

TLS Online TPP Program

#Question id: 14254

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  Determine the height of the packed bed for 95% glucose conversion. Bed diameter is D0 = 0.2 m. Neglect the growth of the hybridomas and assume first order kinetics. 

TLS Online TPP Program

#Question id: 14255

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  If Yp/s is 4 mg Mab/g glu, determine the effluent Mab concentration of the system?

TLS Online TPP Program

#Question id: 14256

#Section 5: Bioprocess Engineering and Process Biotechnology

Hybridoma cells immobilized on surfaces of Sephadex beads are used in a packed column for production of monoclonoal antibodies (Mab). Hybridoma concentration is approximately X = 5 g/l in the bed. The flow rate of the synthetic medium and glucose concentration are Q = 2 l/h and S0 = 40 g/l, respectively. The rate constant for Mab formation is k = 1 gX/l-d. Assume that there are no diffusion limitations and glucose is the rate limiting nutrient.  If Yp/s is 4 mg Mab/g glu, determine productivity of the system? __________________