TLS Online TPP Program

#Question id: 413


The hydrolysis of ATP has a large negative DG'°; nevertheless it is stable in solution due to:

#Section 4: Fundamentals of Biological Engineering
  1. entropy stabilization.

  2. ionization of the phosphates.

  3. resonance stabilization.

  4. the hydrolysis reaction having a large activation energy.

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TLS Online TPP Program

#Question id: 14223

#Section 5: Bioprocess Engineering and Process Biotechnology

A furnace wall is constructed of firebrick 15-cm thick. The temperature inside the wall is 700⁰C the temperature outside is 80⁰C. If the thermal conductivity of the brick under these conditions is 0.3 W m-1 K^-1, what is the rate of heat loss through 1.5 m2 of wall surface?

TLS Online TPP Program

#Question id: 14224

#Section 5: Bioprocess Engineering and Process Biotechnology

Heat is transferred from one fluid to a second fluid across a metal wall. The film coefficients are 1.2 and 1.7kW m^-2 K^- 1. The metal is 6-mm thick and has a thermal conductivity of 19 W m^-1 K^-1. On one side of the wall there is a scale deposit with a fouling factor estimated at 19 W m^-1 K^-1. What is the overall heat-transfer coefficient?

TLS Online TPP Program

#Question id: 14225

#Section 5: Bioprocess Engineering and Process Biotechnology

A fermenter is maintained at 35⁰C by water circulating at a rate of 0.5 kg s^-1 in a cooling coil inside the vessel. The inlet and outlet temperatures of the water are 8⁰C and 15⁰C respectively. The length of the cooling coil is increased by 50%. In order to maintain the same fermentation temperature, the rate of heat removal must be kept the same. Determine the new cooling-water flow rate and outlet temperature by carrying out the following calculations. The heat capacity of the cooling water can be taken as 4.18 kJ kg^- 1 o C^- 1. From a steady-state energy balance on the cooling water, calculate the rate of cooling with the original coil ___________________.

TLS Online TPP Program

#Question id: 14226

#Section 5: Bioprocess Engineering and Process Biotechnology

A fermenter is maintained at 35⁰C by water circulating at a rate of 0.5 kg s^-1 in a cooling coil inside the vessel. The inlet and outlet temperatures of the water are 8⁰C and 15⁰C respectively. The length of the cooling coil is increased by 50%. In order to maintain the same fermentation temperature, the rate of heat removal must be kept the same. Determine the new cooling-water flow rate and outlet temperature by carrying out the following calculations. The heat capacity of the cooling water can be taken as 4.18 kJ kg^- 1 o C^- 1. Determine the mean temperature difference with the original coil.

TLS Online TPP Program

#Question id: 14227

#Section 5: Bioprocess Engineering and Process Biotechnology

A fermenter is maintained at 35⁰C by water circulating at a rate of 0.5 kg s^-1 in a cooling coil inside the vessel. The inlet and outlet temperatures of the water are 8⁰C and 15⁰C respectively. The length of the cooling coil is increased by 50%. In order to maintain the same fermentation temperature, the rate of heat removal must be kept the same. Determine the new cooling-water flow rate and outlet temperature by carrying out the following calculations. The heat capacity of the cooling water can be taken as 4.18 kJ kg^- 1 o C^- 1. Evaluate UA for the original coil. ________________

TLS Online TPP Program

#Question id: 14228

#Section 5: Bioprocess Engineering and Process Biotechnology

A fermenter is maintained at 35⁰C by water circulating at a rate of 0.5 kg s^-1 in a cooling coil inside the vessel. The inlet and outlet temperatures of the water are 8⁰C and 15⁰C respectively. The length of the cooling coil is increased by 50%. In order to maintain the same fermentation temperature, the rate of heat removal must be kept the same. Determine the new cooling-water flow rate and outlet temperature by carrying out the following calculations. The heat capacity of the cooling water can be taken as 4.18 kJ kg^- 1 o C^- 1. If the length of the coil is increased by 50⁰C the area available for heat transfer, A ', also increases by 50% so that A' = 1.5 A. The value of the overall heat-transfer coefficient is not expected to change very much. For the new coil, what is the value of UA’  ______________