#Question id: 14162
#Section 4: Fundamentals of Biological Engineering
A continuous process is set up for treatment of wastewater. Each day, 105 kg cellulose and 103 kg bacteria enter in the feed stream, while 104 kg cellulose and 1.5 x 104 kg bacteria leave in the effluent. The rate of cellulose digestion by the bacteria is 7 x 104 kg d-1. The rate of bacterial growth is 2 x 104 kg d-1 ; the rate of cell death by lysis is 5 x 102 kg d-1. Write balances for cellulose and bacteria in the system.
#Question id: 14162
#Section 5: Bioprocess Engineering and Process Biotechnology
A continuous process is set up for treatment of wastewater. Each day, 105 kg cellulose and 103 kg bacteria enter in the feed stream, while 104 kg cellulose and 1.5 x 104 kg bacteria leave in the effluent. The rate of cellulose digestion by the bacteria is 7 x 104 kg d-1. The rate of bacterial growth is 2 x 104 kg d-1 ; the rate of cell death by lysis is 5 x 102 kg d-1. Write balances for cellulose and bacteria in the system.
#Question id: 14163
#Section 4: Fundamentals of Biological Engineering
A stream of growth medium containing 60% glucose and 40% growth factor A flowing at 500 kg per hour was divided into two feed streams for different cell cultures. One fourth of the growth medium was sent to fermenter 1 and the rest was sent to fermenter 2. What is the flow rates of glucose and growth factor A in the feed streams for the two fermenters
#Question id: 14163
#Section 5: Bioprocess Engineering and Process Biotechnology
A stream of growth medium containing 60% glucose and 40% growth factor A flowing at 500 kg per hour was divided into two feed streams for different cell cultures. One fourth of the growth medium was sent to fermenter 1 and the rest was sent to fermenter 2. What is the flow rates of glucose and growth factor A in the feed streams for the two fermenters
#Question id: 14164
#Section 4: Fundamentals of Biological Engineering
Stoichiometric equations are used to represent growth of
microorganisms provided a ' molecular formula' for the cells is available. The
molecular formula for biomass is obtained by measuring the amounts of C, N, H,
O and other elements in cells. For a particular bacterial strain, the molecular
formula was determined to be C4.4H7.30 1.2N0.86
. These bacteria are grown under aerobic conditions with hexadecane (C16H34)
as substrate. The reaction equation describing growth is:
Assuming 100% conversion, what is the yield of cells from hexadecane in g g-l?
#Question id: 14164
#Section 5: Bioprocess Engineering and Process Biotechnology
Stoichiometric equations are used to represent growth of
microorganisms provided a ' molecular formula' for the cells is available. The
molecular formula for biomass is obtained by measuring the amounts of C, N, H,
O and other elements in cells. For a particular bacterial strain, the molecular
formula was determined to be C4.4H7.30 1.2N0.86
. These bacteria are grown under aerobic conditions with hexadecane (C16H34)
as substrate. The reaction equation describing growth is:
Assuming 100% conversion, what is the yield of cells from hexadecane in g g-l?