#Question id: 382
#SCPH05 I Biotechnology
The molar ratio of sodium acetate to acetic acid in a buffer solution with a pH OF 5.76 is 10:1. Assuming the total buffer concentration is 2.2 X 10-2 mol/L, how many grams of sodium acetate (m.w. 82) and how many grams of acetic acid (m.w. 60) should be used in preparing a litre of the solution?
#Question id: 382
#SCPH05 I Biotechnology
The molar ratio of sodium acetate to acetic acid in a buffer solution with a pH OF 5.76 is 10:1. Assuming the total buffer concentration is 2.2 X 10-2 mol/L, how many grams of sodium acetate (m.w. 82) and how many grams of acetic acid (m.w. 60) should be used in preparing a litre of the solution?
#Question id: 383
#SCPH05 I Biotechnology
Three buffers are made by combining a 1 M solution of acetic acid with a 1 M solution of sodium acetate in the ratios shown below
|
1 M acetic acid |
1 M sodium acetate |
|
Buffer 1: 10 mL |
90 mL |
|
Buffer 2: 50 mL |
50 mL |
|
Buffer 3: 90 mL |
10 mL |
Which of these statements is true of the resulting buffers?
#Question id: 383
#SCPH05 I Biotechnology
Three buffers are made by combining a 1 M solution of acetic acid with a 1 M solution of sodium acetate in the ratios shown below
|
1 M acetic acid |
1 M sodium acetate |
|
Buffer 1: 10 mL |
90 mL |
|
Buffer 2: 50 mL |
50 mL |
|
Buffer 3: 90 mL |
10 mL |
Which of these statements is true of the resulting buffers?
#Question id: 384
#SCPH05 I Biotechnology
A solution was prepared by dissolving 0.02 moles of acetic acid (HOAc; pKa = 4.8) in water to give 1 liter of solution. What is the pH? To this solution was then added 0.008 moles of concentrated sodium hydroxide (NaOH). What is the new pH? (In this problem, you may ignore changes in volume due to the addition of NaOH).
#Question id: 384
#SCPH05 I Biotechnology
A solution was prepared by dissolving 0.02 moles of acetic acid (HOAc; pKa = 4.8) in water to give 1 liter of solution. What is the pH? To this solution was then added 0.008 moles of concentrated sodium hydroxide (NaOH). What is the new pH? (In this problem, you may ignore changes in volume due to the addition of NaOH).